You are watching: Do diagonals bisect each other in a parallelogram

With that being said, ns was wondering if within parallel the diagonals bisect the angles which the meet.

For instance, please describe the link, does $\overlineAC$ bisect $\angle BAD$ and $\angle DCB$?

If castle diagonals do undoubtedly bisect the angles which they meet, can you please, in layman"s terms, show your proof?

Thanks, guys!

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edited may 21 "20 in ~ 10:41

amWhy

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asked Jun 3 "16 in ~ 16:45

RidhwaanRidhwaan

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$\begingroup$ Yes however not a regular parallelogram, only in a square, rhombus and also kite. $\endgroup$

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Jun 3 "16 in ~ 17:11

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The diagonals bisect angles just if the political parties are all of equal length.

Proof -

Assume that the diagonals undoubtedly bisect angles.

Then $\angle BCE=\angle ECD$ in her diagram.

Also $\angle ECD=\angle EAB$ because $AB \| DC$.

So $\angle BCE = \angle EAB$, hence $\triangle BAC$ is isosceles with $AB=BC$.

Similar arguments likewise prove equality of various other sides, $BC=CD$ and also $CD=DA$.

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answered Jun 3 "16 in ~ 16:53

KalElKalEl

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Nope it doesn"t...We have the right to prove it utilizing congruency triangle.U have the right to see the vertically opposite angles space equal.Not the diagonal bisect angle

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answered may 15 "19 in ~ 5:11

HEPIN RAJESHBHAI SAVALIYAHEPIN RAJESHBHAI SAVALIYA

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